The iridium compound loses a pyridine molecule to form a simpler structure that helps transfer polarization during the SABRE process.
Scientific Claim
The iridium complex IrCl(H)2(COE)(py)2 undergoes pyridine loss to form a 16-electron intermediate species with equivalent hydride ligands, which is a key step in the SABRE process.
Evidence Quality Assessment
Claim Status
appropriately stated
Study Design Support
Design supports claim
Appropriate Language Strength
association
Can only show association/correlation
Assessment Explanation
The study describes an observed association between the complex and the pyridine loss process. The language 'undergoes' is appropriate for describing an observed chemical transformation.
More Accurate Statement
“The iridium complex IrCl(H)2(COE)(py)2 is associated with pyridine loss to form a 16-electron intermediate species with equivalent hydride ligands, which is part of the SABRE process.”
Source Excerpt
“2 undergoes py loss to form 16-electron IrCl(H)2(COE)(py) (3), with equivalent hydride ligands.”
Evidence from Studies
Supporting Evidence (1)
The study explicitly describes the pyridine loss from IrCl(H)2(COE)(py)2 to form a 16-electron species with equivalent hydride ligands. This is a key mechanistic step in the SABRE process described in the study.